编程-域名反转功能

题目描述

• 实现两个线程交替打印1-100

代码实现

1. Condition 版本

import java.util.concurrent.locks.Condition;
import java.util.concurrent.locks.Lock;
import java.util.concurrent.locks.ReentrantLock;

// 资源类
// 等待 业务 通知
class Data2{
    private int number = 0;

    Lock lock = new ReentrantLock();

    // Condition取代了对象监视器
    Condition condition = lock.newCondition();

    // + 1
    public void increment() throws InterruptedException {
        lock.lock();

        try {
            while (number %2 != 0){
                // 等待操作
                condition.await();
            }
            number ++;
            System.out.println(Thread.currentThread().getName()+"--->"+number);
            // 通知线程 + 1完毕
            condition.signalAll();
        }catch (Exception e) {
            e.printStackTrace();
        }finally {
            lock.unlock();
        }
    }



    public void increment2() throws InterruptedException {
        lock.lock();

        try {
            while (number % 2 ==  0){
                // 等待操作
                condition.await();
            }
            number ++;
            System.out.println(Thread.currentThread().getName()+"--->"+number);
            // 通知线程 + 1完毕
            condition.signalAll();
        }catch (Exception e) {
            e.printStackTrace();
        }finally {
            lock.unlock();
        }
    }
}

public class B {
    public static void main(String[] args) {

        Data2 data2 = new Data2();

        new Thread(() -> {
            for (int i = 0; i < 10; i++) {
                try {
                    data2.increment();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
        }, "A").start();
        new Thread(() -> {
            for (int i = 0; i < 10; i++) {
                try {
                    data2.increment2();
                } catch (InterruptedException e) {
                    e.printStackTrace();
                }
            }
        }, "B").start();
    }
}

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